Question

Someone please explain how to solve this? Thanks!
https://media.glynlyon.com/g_alg01_2013/8/2b30.gif

Answer 1

I'll try to help you out.
Firstly, try finding what is common in both the terms in the numerator.

Answer 2

ok, one sec...

Answer 3

Is it 2?

Answer 4

Awesome. You are doing good. 8 and 6 have 2 in common. Do \[\sqrt{x^7}\] and \[\sqrt{x^5}\] have anything in common?

Answer 5

x, but the exponents don't have anything in common...

Answer 6

\[\sqrt{x^7}=\sqrt{x^4.x^3}\]
Similarly, \[\sqrt{x^5} = \sqrt{x^4.x}\]
Now, do you see anything in common?

Answer 7

oh, ok, so I have to factor It out?

Answer 8

Yes.

Answer 9

Actually, since you have only \[2\sqrt{x^3}\] in the denominator, try factoring out only that from the denominator. Just because you can cancel them out easily.

Answer 10

*try factoring out only that from the NUMERATOR

Answer 11

couldn't it also be \[\sqrt{x^5} = \sqrt{x^3} \times \sqrt{x^2}\] in the numerator?

Answer 12

Exactly. That's what I am talking about. You are ding absolutely great!

Answer 13

Oh, forgive my spelling mistakes.

Answer 14

Actually : \[\sqrt{x^5}=\sqrt{x^3 \times x^2}\] haha it's ok :)

Answer 15

Well, \[\sqrt{x^3.x^2} = \sqrt{x^3} . \sqrt{x^2}\] So you are correct both the ways.

Answer 16

oh ok :) haha

Answer 17

So, you got it? LEt me know what answer you got. Just to double-check.

Answer 18

Okey Doke :) one sec...

Answer 19

\[4x^2+3x\]

Answer 20

Almost right. I am sure that you didn't knew that you typed a "+" instead of a "-". It should be \[4x^2 - 3x\]

Answer 21

Just a random question: what grade are you in?

Answer 22

10th :) haha I'm a little slow on this subject

Answer 23

USA? or somewhere in Southeast Asia?

Answer 24

haha USA :)

Answer 25

Woah! That's kinda surprising. Anyways, I don't know how the pre-college education in this country works. I graduated high school in India and then moved to the US.

Answer 26

haha surprising? :) well, what do you wanna know?

Answer 27

haha I wasn't expecting a 10th grader to learn solving algebraic equations. That's what I wanted to say :-)

Answer 28

haha yep :) well, I am in 9th grade but some of my classes have been moved up a level because I am supposedly "advanced" haha :) most people in my grade are on Pre-Algebra :)

Answer 29

Since you have three more years to enter college, I have an advice for you: Try completing math until Pre-Calculus or if you can, Calculus I too. It'll be very helpful after you you start college.

Answer 30

Because you are supposedly "advanced"!

Answer 31

Have fun in school. If you have any questions in math, science, about college or anything, just shoot me a message. I'll get back to you as soon as possible. Or you can search me on skype (same username) :)

Answer 32

hahaha I didn't mean to sound like I was bragging lol :) ok, yeah.. this is my second year in Algebra. I didn't feel ready to move on to algebra 2 this year so I chose to do it again and I'm glad I did. Now I get to fully understand the things that were briefly taught. :)

Answer 33

Haha I never thought you were bragging. I actually felt that you were being down to earth.

Answer 34

haha I think it came off a little like that :) Well, thanks for helping me :)

Answer 35

np :)