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what do you get when you factor n^2 + 7n + 10
What two numbers multiply to 10 (last term) and add to 7 (middle coefficient)
more like (n+5)(n+2)
now factor n^2 + 2n - 15
good
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so... \[\Large \frac{n^2 + 7n + 10}{n^2 + 2n - 15}\] turns into \[\Large \frac{(n+5)(n+2)}{(n + 5)(n - 3)}\]
What's next?
very good, the final answer is \[\Large \frac{n+2}{n-3}\] or written out in plaintext form it's (n + 2)/(n - 3) like you have
the same steps are used to simplify #2
You have all the steps correct and the final answer correct. Nice work.
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Oh and I'm sure you meant to say n^2 - 7n + 12 instead of n^2 - 7n + 10, but that's ok, I knew what you meant
you're welcome
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