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Find the standard form of the equation of the parabola given vertex and two points.
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Vertex = (3,1) Point A = (2,0) Point B = (4,0)
@whpalmer4
Same approach should work
How do I do it with 2 points? :/
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Ignore 1 of them? :-) No, they are a clue as to which way the parabola opens
y = a(x-h)^2+k 0 = a(2-3)^2+1 0 = a+1 a = -1 y= -1(x-3)^2+1 I'm confused on what to do now :/
Once you know that, you know which form to use, and you can use either point to fit the parabola
Put in standard form and you are done
y-1 = -1(x-3)^2 -y+1 = (x-3)^2 -(y-1) = (x-3)^2 would this be correct?
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Expand it to ax^2+bx+c Gotta go, good luck!
thanks :D
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