Right circular cone the height= diameter when height = 2.98 cm find the volume of the cone (by approximation using mean value theorem )
tell me how i start or give me hints and i will complete
lol uhm circle is pie radius squared
hold on
@kadkins15 i know the volume of cone \[V=\frac{ 1 }{ 3 }\pi r ^{2}h\]
okay well i k that h is 2.98 pie is 3.14 and your radius^3 is what ur trying to find
trying to find the volume by approximation using mean value theorem
@ganeshie8 can u plz help me with this
v=1/2(3.14)r^3(2.8)
i meant 1/2(3.14)
1/3(3.14
i know it's easy to find it using calculator by i want to find it using approximation by mean value theorem
give me a second ill b rite bck
http://www.sosmath.com/calculus/diff/der11/der11.html Does this help at all? XD
@Fantalux i know everything about MVT it's about the question , no it doesn't help thanks anyway lol
is this calculus or what??
ikr
no the teacher just game the question i don't know from where did he bring it
gave *
What does this mean? As usual, let us utilize an example to grasp the concept. Visualize (or graph) the function f(x)=x^{3}. Choose an interval (anything will work), but for the sake of simplicity, [0,2]. Draw a line going from point (0,0) to (2,8). Between the points x = 0 and x = 2 exists a number x = c, where the derivative of f at point c is equal to the slope of the line you drew. Solution: 1: Using the definition of the mean value theorem {f(b)-f(a) \over b-a} insert values. Our chosen interval is [0,2]. So, we have {\frac {f(2)-f(0)}{2-0}}={\frac {8}{2}}=4 2: By the definition of the mean value theorem, we know that somewhere in the interval exists a point that has the same slope as that point. Thus, let us take the derivative to find this point x = c. {\frac {dy}{dx}}=3x^{2} Now, we know that the slope of the point is 4. So, the derivative at this point c is 4. Thus, 4=3x^{2}. The square root of 4/3 is the point.
does that help at all
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volume = 1/3 ((0.5h)^2 pi))*h
@ikram002p i know how to find the area of cone but i want to use approximation using mean value theorem
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lol i knw .. just find a function of volume then use mean value thm
ok :)
hope that helps i gotta go bro but yeahh
thanks bro
so u have h=2.98 .... h'=3 v=pi/12 h^3 v'=pi/4 h^2 \[f(h)\approx f(h')+f'(h')(h-h')\]
aha thanks @ikram002p
i've made a mistake in the value of h' when i solved it first time lol
so its good nw ha ?!
yup thank you so much :)
np :)
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