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if the speed o an object in uniform circular motion is doubled and the radius remains constant then the centripetal acceleration increases by a factor of
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\[F _{c} = mv ^{2}/r\]
if speed is doubled means 2V then \[F = m (2V)^{2}/r \]
\[F = 4mv ^{2}/r\]
F = ma = 4mv^2/r So acceleration increases by a factor of 4 .
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a=v2/r double v = quadruple a
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