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Mathematics 20 Online
OpenStudy (anonymous):

Please help me to proof this guys..

OpenStudy (anonymous):

\[\sqrt{N + 1}-\sqrt{N}=1/ (\sqrt{N+1}+\sqrt{N})\] Use this to explain why \[\sqrt{101}\] is close to, but slightly less than, 10.05

OpenStudy (***[isuru]***):

substitute N = 100 for the equation given...

OpenStudy (***[isuru]***):

u will get.. \[\sqrt{100 +1} - \sqrt{100} = \frac{ 1 }{ \sqrt{100 +1} + \sqrt{100}}\]

OpenStudy (raden):

hint : times by conyugate of √(N+1) - √N, then simplify

OpenStudy (***[isuru]***):

since... sqrt(100 ) = 10 u can simplify this in to \[\sqrt{101} - 10 = \frac{ 1 }{ \sqrt{101}+ 10 }\]

OpenStudy (***[isuru]***):

now... \[\sqrt{101} = \frac{ 1 }{ \sqrt{101} + 10 } + 10\]

OpenStudy (anonymous):

yups but at the end I got \[\sqrt{101} = \sqrt{101}\] ??

OpenStudy (***[isuru]***):

1/10 = 0.1 so.. 1/ ( sqrt[101] + 10 ) should be even smaller than that... because the the value of an fraction decreases when the denominator increase so 1/ ( sqrt[101] + 10 ) is lesser than 0.1 which means the sqrt(101) is less than 10.01 furthermore sqrt(100) = 10 therefore sqrt(101) should equal to a value which is little bit higher than 10 if sqrt(101) was equal to 10 then 1/ ( sqrt[101] + 10 ) will become 1/20 which is 0.5 and therefore the value of sqrt(101) will become 10.5 but sqrt(101) is little bit higher than 10 therefore the value of 1/ ( sqrt[101] + 10 ) will be a little bit lower than 0.5 which mean sqrt(101) is close to 10.05 but it's a little bit less than that

OpenStudy (***[isuru]***):

got it :) ?

OpenStudy (anonymous):

Oh my God you are awesome! now I understand why.. Thanks!!

OpenStudy (***[isuru]***):

u r welcome!

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