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Mathematics 7 Online
OpenStudy (anonymous):

I need someone who's good at using the quadratic formula

OpenStudy (anonymous):

Please post your question.

OpenStudy (anonymous):

There @silversurfer

OpenStudy (anonymous):

Can you tell under what condition the ball hits the ground ?

OpenStudy (anonymous):

h=0

OpenStudy (anonymous):

The height has to become zero,right? So, you make h=0 and equate the quadratic part to zero. Then, you just solve for x, in this case, this is the variable t.

OpenStudy (anonymous):

The quadratic equation can be rewritten as 5t^2+5t-45=0. Then you can simplify it further by dividing with 5 on both sides, doing which gives you t^2+1-9=0. Now, you can use the quadratic formula given below.

OpenStudy (anonymous):

\[t^2 -t-9=0\]

OpenStudy (anonymous):

using the quadratic formula: \[t=\frac{-b \pm \sqrt{b^2 -4ac}}{2a}\]

OpenStudy (anonymous):

A correction to my previous equation, it would be t^2+t-9=0. Sorry, it was careless of me.

OpenStudy (anonymous):

yes indeed: t^2 + t - 9 =0 :P

OpenStudy (anonymous):

Then use the formula given by sayak to solve for t. Keep in mind, the equation is of the form ax+bx+c=0 where x is t in this case.Hope this helps.

OpenStudy (anonymous):

yes but how do i solve for t and find out the seconds?

OpenStudy (anonymous):

\[t=\frac{\sqrt{37}-1}{2}\]

OpenStudy (anonymous):

a=1,b=1,c=-9, plug in the values in the formula now. I haven't checked but if you get a negative time as one of the roots, you can rule that out.

OpenStudy (anonymous):

which should approximately be equal to 2.5

OpenStudy (anonymous):

@getoffmyback got it?

OpenStudy (anonymous):

yes I'm following

OpenStudy (anonymous):

Clearly speaking, there would be two answers. Check for yourself to see which one is reasonable.

OpenStudy (anonymous):

yes it gives me an option of just one

OpenStudy (anonymous):

@sayakdbz I have to round to the nearest hundredth

OpenStudy (anonymous):

nearest hundredth? hm...

OpenStudy (anonymous):

That means one of the answers won't be reasonable. Don't be daunted at that, you will understand for yourself once you calculate the two values.

OpenStudy (anonymous):

yea @sayakdbz

OpenStudy (anonymous):

I already gave the answer needed: 2.5 which is: t=\frac{sqrt{37}-1}{2}

OpenStudy (anonymous):

\[t=\frac{\sqrt{37}-1}{2}\]

OpenStudy (anonymous):

rounding 2.5 to the nearest 100th

OpenStudy (anonymous):

oh I thought that was the tenth

OpenStudy (anonymous):

my bad

OpenStudy (anonymous):

wait, sorry :P i approximated the original answer rounded off to the nearest 100th the answer is 2.54 seconds

OpenStudy (anonymous):

well thank u all for your help @silversurfer @sayakdbz and @isag

OpenStudy (anonymous):

@getoffmyback u are most welcome

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