Question

Simplify. Identify any x-values for which the expression is undefined.

Answer 1

I dont understand how to do this. If you could explain it that would be great. thanks in advanced (:

Answer 2

SOLO TIENES QUE HACER QUE EL DENOMINADOR SE DIFERENTE A CERO YA QUE LA EXPRESION NO EXISTIRA SI SU DENOMINADOR ES IGUAL A CERO \[6X ^{2} -23X +7 \neq 0\]
HACIENDO HASPA SIMPLE QUEDA :
\[(2X-7)(3X-1) \neq 0\]
ENTONCES
\[2X-7 \neq 0 \] o \[3x-1 \neq 0\]

enonces X es diferente de 7/2 y 1/3 por lo tanto la expresion queda definida para
\[\mathbb{R} -\left\{ 7/2;1/3 \right\}\]

Answer 3

hello @LilVeroDez13
use the discriminant rule
\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
then you will found the roots and then change it to become a factor.
then you can choose x in the denominator to become 0 to make it undefined

Answer 4

@SOTELOCAMONES gracias pero no es correcto con mi problema. And I understand more in english (: but thanks. gracias.

@edwinls9 thanks I will try that :)

Answer 5

@edwinls9 wait, which numbers would be b.. im not sure how to plug it all in.

Answer 6

okay basically
\[ax^{2}+bx+c\]
in your denominator
\[6x^{2}-23x\]
then a = 6, b=-23, c = 7

Answer 7

i mean \[6x ^{2}-23x+7\]
then when you calculate it you
should get that x= 7/2 and x=1/3
have u go through this?

Answer 8

I think I have. I Jus dont remember about it. But thanks!

Answer 9

your welcome! goodluck!

Answer 10

thanks! (: