Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

algebra 2

OpenStudy (anonymous):

@agent0smith last one I think!!

OpenStudy (agent0smith):

Plug in n=1, that's your first term. Then n=2, then 3 then 4

OpenStudy (anonymous):

i left my graphing calculator at home.. that's why I need so much help

OpenStudy (agent0smith):

You don't really need one.

OpenStudy (anonymous):

i cant do exponents on my calculator

OpenStudy (agent0smith):

You don't need to, try doing it by hand

OpenStudy (anonymous):

how?

OpenStudy (agent0smith):

By plugging in n's into -4(1/3)^(n-1)

OpenStudy (anonymous):

yeah, i know what but how do i multiply an exponent by hand

OpenStudy (agent0smith):

Plug in n=1 -4(1/3)^(1-1) = -4(1/3)^0

OpenStudy (anonymous):

oh so it's 0?

OpenStudy (agent0smith):

any number to the power of zero equals 1. -4*(1/3)^0 = ?

OpenStudy (anonymous):

-1.33333333333333333333333333333333333333333333

OpenStudy (agent0smith):

Any number to the power of zero is 1, so (1/3)^0 = 1

OpenStudy (anonymous):

oh so -4

OpenStudy (agent0smith):

Now plug in n=2 -4(1/3)^(2-1)

OpenStudy (anonymous):

okay so this time its -1.3333333333333

OpenStudy (agent0smith):

Leave as -4/3 n=3 -4(1/3)^(3-1)

OpenStudy (anonymous):

-.44444444

OpenStudy (agent0smith):

Leave as a fraction, always.

OpenStudy (agent0smith):

Now plug in n=4, that's the fourth term.

OpenStudy (anonymous):

-.148148148

OpenStudy (anonymous):

does it diverge or converge?

OpenStudy (agent0smith):

^leave them all as fractions. -4/9 and -4/27 It converges if the common ratio (the one with the exponent attached) is less than 1. The common ratio is 1/3, so...

OpenStudy (anonymous):

oh, okay I will and so it converges?

OpenStudy (agent0smith):

Oh i forgot to check this... did you manage part c?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!