Question

Im giving medalas and fans. Just started Chemistry yesterday and desperatley need help.
Which bond pair does not have a polar covalent bond?
P – Cl
O – H
S – Cl
H – Cl
Cl – Cl

Answer 1

Which pair has equal protons?

Answer 2

I know what protons are and what not.. But I've never seen those letters in my life.
I'm really new with this

Answer 3

Never??? O.o

"It's dangerous out there. Here, take this: http://www.ptable.com/ "

Answer 4

Well of course I've seen the periodic table xD
Alright I can do the research from here, Thanks!

Answer 5

H - Cl

Answer 6

I feel dumb loooooool

Answer 7

H (+1) - Cl (-1)

Answer 8

Atom number = proton number btw :)

Answer 9

Now, I was pretty sure it's up to the number of protons in the nuclei because that will determine the strength of the pull of the shared electrons. But since Scofflawxx said that, you should look up if that's right.

Answer 10

Polar covalent bonds share unequal bonding electrons, so for example P(-3) - Cl(-1) has an unequal charge which makes it polar and heavily negative charge. H(+1) - Cl(-1) balance each other forming a covalent bond, HCl.

Answer 11

I was pretty sure anything with H will have polarity. I was thinking it's Cl-Cl

Answer 12

I'm bringing out the chem book you might be right hold on

Answer 13

it has to do with the electronegativity of each atom, not the number of protons

Answer 14

Yeah.

Non-polar bonds occur when the difference in electronegativity between the two atoms is less than 0.4
Polar bonds occur when the difference in electronegativity between the two atoms is between 0.4 and 1.7
Ionic bonds occur when the difference in electronegativity between the two atoms is greater than 1.7
-Wikipedia

So then will you have to calculate it? Or is there an easier way to tell by a glance? This is interesting. My way has been to see which element has more protons, making it attract the electron pair to its side. Please explain moar!

Answer 15

So yeah, you're right Cl 3.2 - Cl 3.2 is covalent dang sorry asker

Answer 16

Oh my gosh. Using this info in my notes. Thanks guys xD

Answer 17

You're welcome. Note that my method is not completely right, but it helps me. :) Good luck