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Chemistry 6 Online
OpenStudy (anonymous):

what is the empirical formular of the compound formed by

OpenStudy (anonymous):

a) \[\large Al^{3+}\text{and } Cl^{-}\] b)\[\large Al^{3+}\text{and } O^{2-}\] c)\[\large Mg^{2+}\text{and } NO_2^{-}\]

OpenStudy (anonymous):

is this the corresponding chemical formular a)\[\large Al_2Cl\] b)\[\large Al_2O_3\] c)\[\large MgNO\]

OpenStudy (jfraser):

b is correct, but a and c need work. Al has a +3 charge, and Cl has a -1. If you put together 2 Al ions, each of which is a +3, that's a charge of +6. There must be a a balance of charge in ionic compounds, so that the sum of the pieces adds up to zero.

OpenStudy (anonymous):

a) AlCl_3 c) Mg(NO_3 )_2.

OpenStudy (jfraser):

yes

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