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Mathematics 15 Online
OpenStudy (anonymous):

1. Use the net to find the surface of the cylinder. about 273 m^2 about 179 m^2 about 302 m^2 about 151 m^2

OpenStudy (anonymous):

OpenStudy (anonymous):

Can you help?

OpenStudy (jdoe0001):

notice the RADIUS of our circular top and circular bottom, is 3 units, meters in this case so \(\bf \textit{Area of a Circle}=2\pi r\qquad \textit{Area of a Circle}=2\pi \cdot {\color{red}{ 3}}\) we sum those 2 Areas first

OpenStudy (jdoe0001):

so \(\bf 2\pi \cdot {\color{red}{ 3}}+2\pi \cdot {\color{red}{ 3}}\) will be the Area of the circular top and bottom of the cylinder

OpenStudy (jdoe0001):

ohh shoot wait a second

OpenStudy (jdoe0001):

I got the wrong.... eqution there.. anyhow.. lemme fix that quick

OpenStudy (anonymous):

Alright.

OpenStudy (jdoe0001):

\(\bf \textit{Area of a Circle}=\pi r^2\qquad \textit{Area of a Circle}=\pi \cdot {\color{red}{ 3}}^2\\ \quad \\ \textit{sum of both circles will be }\pi \cdot {\color{red}{ 3}}^2+\pi \cdot {\color{red}{ 3}}^2\)

OpenStudy (anonymous):

The answer I got is 113.04. But that can't be right considering it's not any of the answer choices.

OpenStudy (jdoe0001):

so now to do the side of the cylinder, the long part we know is 13 units high so how long is it? well, it runs along the border of the circles atop and bottom so is as long as the circles are well, how long are the circles? well \(\bf \textit{circumference of a circle}=2\pi r\qquad \textit{circumference of a circle}=2\pi {\color{red}{ 3}}\\ \quad \\ \textit{so the long part is }2\pi {\color{red}{ 3}}\quad \textit{long and is }13\quad wide\qquad thus\\ \quad \\ \textit{Area of the side of the cylinder}=2\pi {\color{red}{ 3}}\times 13\)

OpenStudy (anonymous):

So the answer would be 151 m^2?

OpenStudy (anonymous):

Which means I would have to round it and then it would be 302 m^2. :)

OpenStudy (anonymous):

Correct?

OpenStudy (jdoe0001):

well, sure if you want to round it up, yes

OpenStudy (anonymous):

Great! Thanks. :) Can you help with my two other questions?

OpenStudy (jdoe0001):

well.. is easier if you post anew, thus more exposure and we can revise each other :)

OpenStudy (anonymous):

Alright!

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