Question

Step by Step please
Solution of...
http://awesomescreenshot.com/0502bl7743

Answer 1

have you covered factoring of quadratics yet?

Answer 2

no...

Answer 3

c

Answer 4

How'd you get that?

Answer 5

i know i know i know

Answer 6

>.>

Answer 7

You just know without working it out? Or you know you're gonna tell me?

Answer 8

how.. you got it..

Answer 9

i know i know i know

Answer 10

c

Answer 11

-.- your trolling is unwelcome here.

Answer 12

There is no need for factorization here.

Answer 13

its c

Answer 14

Then... what's needed?

Answer 15

u

Answer 16

I would believe you if you didn't say it's C on another post... while giving no proof. So stop trolling... please.

Answer 17

Here's a warm-up problem:

Sqrt(5x+1)=5.

How would you solve THAT for x?

Answer 18

How odd @mathmale, I almost posted the same thing.

Answer 19

I honestly don't know... um \[\sqrt{5x+1} = 5\] ? Am I supposed to plug in a zero for x?

Answer 20

wait... nvm that wouldn't work.

Answer 21

Yea... I have no idea.

Answer 22

Solving this "warm-up" problem:
Square both sides of \[\sqrt{5x+1}=5\]

Answer 23

Or, square both sides of Sqrt(5x+1) = 5.

Answer 24

[ Sqrt(5x+1)]^2 = ?
[ 5 ]^2 = ?

Answer 25

I have no idea what to do the first one but
5^2=25...

Answer 26

Sorry I really have barely any knowledge in math whatsoever

Answer 27

[ Sqrt(6)]^2 = 6
[ Sqrt(5x)]^2 = 5x
[ Sqrt (5x+1)]^2 = ??

Answer 28

5x+1?

Answer 29

Yes, so that you end up with the equation 5x+1=25.

Solve that for 5x, please, and then solve the result for x alone.

Answer 30

I'm sorry... I'm really flustered >-<
Did you get the 25 from 5^2?
I don't see any number that fits as x to equal 25 .-.

Answer 31

You obtained that 25 yourself by squaring 5.

[ Sqrt(5x+1)]^2 = [ 5 ]^2 => 5x+1=25. Solve for x.

Answer 32

Oh.... oops. Solving for x... do I subtract one from both sides?

Answer 33

Yes. Then 5x = 24 and x = ??

Answer 34

x = 4.8?

Answer 35

or x = 24/5. Yes!

Now, back to the original problem:

Sqrt(5x+1) - Sqrt(x) = 5

Please add Sqrt(x) to both sides and simplify the result. We can discuss WHY later on.

Answer 36

\[(\sqrt{5x+1})^2 - (\sqrt{x})^2 = 5^2\]

\[5x+1 - x = 25\]

Did I mess up yet? >.<

\[x = 6\] ?

Answer 37

I'd rather not talk in terms of "messing up." But I did ask you to add Sqrt(x) to both sides of the equation Sqrt(5x+1) - Sqrt(x) = 5. Have you done that?

Answer 38

Well I thought I did /.\ I suppose I didn't...

Answer 39

Siimplify:

Sqrt(5x+1) - Sqrt(x) + Sqrt(x) = 5 + Sqrt(x) (I've added Sqrt(x) to both sides!

Answer 40

5x + 1 - x + x = 5 + x ...

Answer 41

Ugh I think I'm just going to quit .-. I'm just not getting this

Answer 42

Strong hint, Angel: -Sqrt(x) + Sqrt(x) = 0. Do NOT remove the Sqrt operators on the left side, as you have done.

Answer 43

You should end up with Sqrt(5x+1) = 5 + Sqrt(x).

If you are tired and frustrated, stop now and re-post the same question tomorrow morning. What do you intend to do now?

Answer 44

Oh.. did you cancel out -Sqrt(x) by adding it to both sides?
Sorry... maybe you're right...
I kinda took some sleepy medicine awhile ago.
If I still can't understand anything I'll just try again in the AM

Answer 45

OK: let's review where we are.

You have Sqrt(5x+1)=5+Sqrt(x).

We must get rid of that Sqrt operator. on both sides.
Therefore, square Sqrt(5x+1). Result: 5x + 1.
Square (5+Sqrt(x)). This is much more complicated; the correct result is

5^2 + 2Sqrt(x) + [Sqrt(x)]^2, or 25 +2Sqrt(x) + x.

Answer 46

You decide: if this makes sense, let's continue; if it does not, repost this question in the morning when you're fresher.

Answer 47

Um... I thought I was getting it... but I don't think so. I'll just go to sleep and try again in the morning... thank you for your patience. I appreciate it .

Answer 48

Rest well. Hope to "see" you online tomorrow.

Answer 49

Lol we'll see. Thank you and hopefully you do as well. Good nighhhht.