find the complex zeros of the polynomial function. write f in factored form f(x)=x^4+12x^2+11
try thinking about it like how would you have factored x^2 + 12x + 11 ?
do you put the like terms together
mmm I don't see how there are like terms?
yeah i hate math so im confused
factor x^2 + 12x + 11 do you know how to do that?
no
well how about like this x^2 + 6x + 5 = (x + 5)(x+1) because 5+1=6 (the middle term) and 5*1=5 (the third term)
so it would be (x+11)(x+1)
yep! :) then x^4 + 12x^2 + 11 is the same idea just replace x with x^2 in the factored form :) like x^4 + 6x^2 + 5 = (x^2 + 5)(x^2 + 1)
ok so x^4+12x^2+11=(x^4+12)(x^4+11)
mmm not quite :) x^4 + 6x^2 + 5 = (x^2 + 5)(x^2 + 1) ^ left with x^2 not x^4
so its (x^2+12)(x^2+11) yeah now im confused why is it ^2 and not ^4
(x^2 + 11)(x^2+1) because when you FOIL it (distribute it out) you would get (x^2)(x^2) + 11x^2 + 1x^2 + (1)(11) which simplifies to x^4 + 12x^2 + 11
okay no i get it we are using the FOIL method
so in factored form would be (x^2)(x^2) + 11x^2 + 1x^2 + (1)(11)
mmm that would be the factored form distributed factored form would be (x^2+11)(x^2+1)
ok
so this is factored form using complex zeros (x^2+11)(x^2+1)
then to find the complex zeros find x for each when x^2+11=0 and x^2+1=0
ok so f(x)=
okay they gave me f(x)=(x^2+1)(x^2+11)
hmm?
is it wrong
no?
yes whats the question
write f in factored form f(x)=x^4+12x^2+11 would be f(x)=(x^2+1)(x^2+11) then the other half of the question find the complex zeros of the polynomial function. would be find x for each when x^2+11=0 and x^2+1=0
then it says use the complex zeros to write f in factor form
mmm then yeah, factored form is f(x)=(x^2+1)(x^2+11)
ok
Join our real-time social learning platform and learn together with your friends!