Can someone help me with this question?!?!?!

Question

anonymous · Answer

attachment

anonymous · Answer

@kewlgeek555  @texaschic101

anonymous · Answer

since one factor is more or less given. synthetically divide and find the quadratic term and use the quadratic formula to solve for the imaginary roots

anonymous · Answer

could you solve it and just show me your steps im no good at this!

jdoe0001 · Answer

the choices make an assumption that one of the roots is either (x+2) or (x-2)
test both to see which one is it, then divide the polynomial by that root

you'd end up with a quadratic  as the quotient, with no remainder
so, once with a quadratic, it should be just a matter of factoring or using the quadratic formula

anonymous · Answer

......

jdoe0001 · Answer

$\large x^3+4x^2+7x+6 \div 
\begin{array}{llll}
(x+2)\
\quad or\
(x-2)
\end{array}$

whichever gives a remainder of 0, is the root

jdoe0001 · Answer

$\bf x^3+4x^2+7x+6 \div (x\pm 2)\implies \square x^2+\square x+\square \qquad thus\ \quad \

(x\pm 2)(\square x^2+\square x+\square)$

anonymous · Answer

whats supposed to go in the blanks?

jdoe0001 · Answer

what you'd get from the long division of the polynomial

mertsj · Answer

Do you know synthetic division?

anonymous · Answer

i dont think i did it right

mertsj · Answer

Do you know synthetic division?

anonymous · Answer

i got x+4+ (11x+22)/(x^2 -4)

anonymous · Answer

from the long divion

mertsj · Answer

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