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Mathematics 13 Online
OpenStudy (anonymous):

HELPPPPPP WHAT equation represents the line passing through the points (3, 2) and (−9, 6)?

OpenStudy (jdoe0001):

\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 3}}\quad ,&{\color{blue}{ 2}})\quad &({\color{red}{ -9}}\quad ,&{\color{blue}{ 6}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-y_1={\color{green} m}(x-x_1)\qquad \textit{plug in your values, to find out}\)

OpenStudy (mathmale):

Break the problem sol'n down into 2 parts: (1) find the slope of the line thru the given points; (2) choose one of the points and insert its coordinates, as well as the slope, into the point-slope formula for the eq'n of a str. line: y-y0 = m (x - x0).

OpenStudy (anonymous):

medals for correct answers

OpenStudy (mathmale):

JDOE is again right on target. AG: Please show your stuff now.

OpenStudy (mathmale):

AG: We're helping YOU to obtain the correct answer.

OpenStudy (anonymous):

x − 3y = 9 x + 3y = 9 3x − y = −9 3x + y = 9

OpenStudy (anonymous):

y-3=m(x-2) @jdoe0001

OpenStudy (anonymous):

@wolf1728

OpenStudy (mertsj):

How do you find the slope of a line?

OpenStudy (anonymous):

y=mx+b

OpenStudy (mertsj):

If you have the equation of a line in that form, m is the slope.

OpenStudy (mertsj):

However in your problem you are given two points so you need to use those points to find the slope.

OpenStudy (mertsj):

(3,2) and (-9, 6) are your two points. Which numbers are the y coordinates in those two points?

OpenStudy (anonymous):

idk honestly

OpenStudy (mertsj):

Can you graph an ordered pair?

OpenStudy (anonymous):

maybe

OpenStudy (mertsj):

|dw:1391823061445:dw|

OpenStudy (mertsj):

Copy that drawing and graph the point (2,5)

OpenStudy (anonymous):

|dw:1391823129251:dw|

OpenStudy (anonymous):

like that

OpenStudy (mertsj):

|dw:1391823159839:dw|

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