A random sample of 140 students is chosen from a population of 3,500 students. If the mean IQ in the sample is 105 with a standard deviation of 9, what is the 95% confidence interval for the students' mean IQ score? a 100−120 b107.9−112.1 c 103.5−106.5 d108.66−111.34
you want a 95% confidence interval, right?
yes @abrahamglasser
so the right side will be at .975 and the left side will be at .025 1=.95 = .05 .05 / 2 = .025 (you are taking off .025 off each side to get the interval) .95+.975 0+ .025 = .025 so the z scores are .025 and .975. do you know how to do the rest of it?
I have no idea how to do the rest of it :/
\[z = \frac{ x - \mu }{ \sigma }\] mu is the mean and sigma is the standard deviation now to find the interval \[.025 = \frac{ x - 105 }{ 9 }\] solve for x and that gives you the left side of the interval. now the right side \[.975 = \frac{ x - 105 }{ 9 }\] solve for x and that gives you the right side of the interval. these x's give you the answer
tell me if you dont understand something or if you dont know where i got these values, etc
wait, i think i made a mistake somewhere...
yea the answers weren't coming out right for the right one I got 15.225
105.225*
i have to think about it...
ok
ok got it
i was thinking of a different confidence interval :( sorry about that
ok, so the formula is..\[CI = x \pm Z _{\alpha/2}\times (\sigma/\sqrt n)\] x = Mean σ = Standard Deviation α = 1 - (Confidence Level/100) Zα/2 = Z-table value CI = Confidence Interval
so it is \[105 \pm Z_{.025} * (9/ \sqrt 140)\]
and the z score of .025 is 1.96
ok so what do I do with the z score?
did you see the formula above it?
so it is 105±1.96∗(9/1√40)
i mean 105±1.96∗(9/√40)
that doesn't get me my answer what else do I have to do with that?
it doesn't? hmm.
none of my answer choices.
im pretty sure the actual answer is C) 103.5 - 106.5 i dont know why i keep getting different answers...
That's what I put down to begin with. This whole Exam is so weird. I don't understand it.
lol neither do i :P
although im pretty sure it's the right formula..
whatever. statistics is weird
Thank you so much for helping me. And I think it is. It looks really familiar.
no problem
Thankyou sooo muchh- this was correct!
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