HELP MEEEEEE Which equation represents the line passing through the point (4, −16) and is perpendicular to the line
\[y=-\frac{ 2}{ 3 }x+8\]
Let us begin with our basic line equation. $$y = mx + b$$
ok
its already in that form
Now, we know that, because the line is perpendicular to the first, this line's slope is \(-\frac 1 m\), or the negative reciprocal of that slope.
So $$y = \frac 3 2 x + b$$ so far.
We know that x = 4, y = -16 is a solution to this equation, so we can use that to solve for b.
$$-16 = \frac 3 2 (4) + b$$ What does this simplify to, you think?
2
Er, the equation simplifies to: $$-16 = \frac{12}2 + b\\ -16 = 6 - b\\ -22 = b$$
Sorry, that should be 6 + b.
ooo i thought u was talking about the (4)
That's one way to do it, but you still have to multiply by 3 in the numerator. Therefore, our equation is: $$y = \frac 3 2 x - 22$$
ok then what
never mind
thanx are u up for a few more
Sure, but I'm not doing all the work this time.
LMAO OK
Which equation represents the line passing through the points (3, 2) and (−9, 6)?
we must graph this rite
Well, you could do that. It might help but it's better to just do it with pure mathematics. |dw:1391829104708:dw|
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