Question

Help! Medal and fan im not 100% sure this is the answer ( attached)

Answer 1

What happens when you plug in x = -2?

Answer 2

into the parent function of my answer?

Answer 3

yes, into your answer choice

Answer 4

i got -4.4 i did it another way and got - 0.6

Answer 5

what did you type into the calculator?

Answer 6

(-2-3) = -5
then
log 2 = 0.30
0.30 - 5 - 6 = -10.7

Answer 7

\[\Large y = \log_{2}(x-3) - 6\]


\[\Large y = \frac{\log(x-3)}{\log(2)} - 6 \ ... \ \text{See note below}\]


\[\Large y = \frac{\log(-2-3)}{\log(2)} - 6\]


\[\Large y = ???\]


Note: I'm using the change of base formula on step 2


The change of base formula is \(\Large \log_{b}(x) = \frac{\log(x)}{\log(b)}\)

Answer 8

ok i cant get the log of -5

Answer 9

because the log of any negative number is undefined

Answer 10

so that's why choice C is out

Answer 11

ok i also know that its random for what point they use if its not on the y axis

Answer 12

i dont think it is b either because that would be 0 / log2

Answer 13

then you subtract off 2 to get -2

but (-2,-2) is not on the curve

Answer 14

so yes, B is out too

Answer 15

ok im lost then because if thats the case then neither a or d will work

Answer 16

wait
i just looked again it would be 1/ log 2 so b may be right

Answer 17

Let's try choice A. Let's check and see if (-2,-5) lies on this curve. So if we plug in x = -2, then we should get y = -5 (if this were true).


\[\Large y = \log_{2}(x+3) - 5\]


\[\Large y = \frac{\log(x+3)}{\log(2)} - 5\]


\[\Large y = \frac{\log(-2+3)}{\log(2)} - 5\]


\[\Large y = \frac{\log(1)}{\log(2)} - 5\]


\[\Large y = \frac{0}{0.30103} - 5\]


\[\Large y = 0 - 5\]


\[\Large y = -5\]


Therefore, (-2,-5) lies on choice A. Make sure (5,-2) lies on this curve as well.

Answer 18

thank you it did check out so i just had to fill in for x and solve, our teacher had us trying to do it the other way around lol thx

Answer 19

you're welcome