Another practice problems I'm stuck on:
logbase3(7x+14)-logbase3(x-3)=2
I can use the property rules to make logbase3((7x+14)/(x-3))=2
And then...??

Question

Another practice problems I'm stuck on:
logbase3(7x+14)-logbase3(x-3)=2
I can use the property rules to make logbase3((7x+14)/(x-3))=2
And then...??

ganeshie8 · Answer

good so far, 
next, change to exponent form

ganeshie8 · Answer

$\large   \mathbb{\log_a x   = b}$

means,

$\large   \mathbb{ x   = a^b}$

shamil98 · Answer

$$\large \log_3 \frac{ 7x+14 }{ x-3 } = 2$$
let 7x + 14/x-3 = a
so using the rule above, what do you get ?
$$\large \log_3 a = 2$$
(resub the frac back in after you change to exponent form)

anonymous · Answer

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anonymous · Answer

Oh my goodness, could not decide which was the best response! But that rule logbaseA(x)=b means x=a^b was all I needed to know, and was able to solve it myself. Good practice! Thanks all :)

anonymous · Answer

answer was 41/2 (or 20.5) btw

anonymous · Answer

oh and it's already up there... duh!

anonymous · Answer

yeah ..:)