A constant voltage is applied across a circuit. If the resistance in the circuit is doubled, what is the effect on the power dissipated by the circuit?

The power dissipated is reduced by a factor of 4.
The power dissipated is quadrupled.
The power dissipated is doubled.
The power dissipated is reduced by a factor of 2.
The power dissipated remains constant.

Question

A constant voltage is applied across a circuit. If the resistance in the circuit is doubled, what is the effect on the power dissipated by the circuit?

	 The power dissipated is reduced by a factor of 4.
	 The power dissipated is quadrupled.
	 The power dissipated is doubled.
	 The power dissipated is reduced by a factor of 2.
	 The power dissipated remains constant.

***[isuru]*** · Answer

@hartnn

hartnn · Answer

power dissipated =  i*V = V * (V/R)  = V^2/ R

since V is constant,
power dissipated is inversely proportional to R

hartnn · Answer

so when R doubles, Power dissipated halves

anonymous · Answer

ohh okay, so it would reduced by a factor of 2...thank you

hartnn · Answer

yes!
welcome ^_^