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Mathematics 7 Online
OpenStudy (anonymous):

Simplify the expression. (Expression in the comments below)

OpenStudy (anonymous):

\[4\sqrt{16a^6b^{12}}\]

OpenStudy (anonymous):

@nikato @poopsiedoodle @Mertsj

OpenStudy (mertsj):

Remember that taking the square root is the inverse of raising to the second power so write all of the stuff underneath the radical in the form: (something)^2

OpenStudy (mertsj):

For example: 16=4^2

OpenStudy (nikato):

You can ignore the 4 outside the radical for now. So u have sqrt 16 x sqrt a^6 x sqrt b^12 = 4 x a^3 x b^6 =4a^3b^6 Now remember the 4 we isolated in the beginning So 4(4a^3b^6) =16a^3b^6

OpenStudy (nikato):

Sqrt of a variable is just dividing the exponent by 2

OpenStudy (anonymous):

Okay.

OpenStudy (nikato):

So...do you understand this now?

OpenStudy (anonymous):

So the final answer would conclude to 16a^3b^6? and kind of.. Not fully =/.

OpenStudy (anonymous):

Kind of slow in math sorry lol.

OpenStudy (nikato):

Yes. And what do you by kind of and not fully

OpenStudy (anonymous):

Where you said "sqrt 16 x sqrt a^6 x sqrt b^12" confuses me O_o do you just put square root in front of everything then and ignore the outside?

OpenStudy (anonymous):

and my school said it was wrong >.<

OpenStudy (nikato):

Did I do something wrong?.... Do you know what the correct answer was?

OpenStudy (mertsj):

\[4\sqrt{16a^6b ^{12}}=4\sqrt{4^2(a^3)^2(b^6)^2}=4\sqrt{4^2}\sqrt{(a^3)^2}\sqrt{(b^6)^2}=4(4)(a^3)(b^6)=16a^3b^6\]

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