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Mathematics 13 Online
OpenStudy (anonymous):

If the concentration of sodium ion in this average individual is 0.131 M, what is the mass of sodium ion circulating in 5.0L of blood?

OpenStudy (anonymous):

Use the formula \[c=\frac{n}{v}\]

OpenStudy (anonymous):

\[Also\quad convert\quad 5L\quad to\quad dm^-3\]

OpenStudy (anonymous):

1dm^-3 = 1L

OpenStudy (anonymous):

your saying \[\frac{ .131M }{ 5L }\]

OpenStudy (anonymous):

From the formula you can find the no. of moles of sodium. After that find the relative atomic mass of sodium and use the \[n=\frac{m}{M}\] formula to get the mass

OpenStudy (anonymous):

\[cv=n\]\[.131mol dm^-3*5dm^-3=n\]

OpenStudy (anonymous):

thank you I have to figure out how to put this into my calculator

OpenStudy (anonymous):

Ok take your time :)

OpenStudy (anonymous):

ok so i got\[2.24*10^{02}\] is that correct?

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