A point H on a segment with endpoints B (3, -1) and Z (12, 5) partitions the segment in a 5:1 ratio. Find H. You must show all work to receive credit.
I thought I was supposed to multiply the distance between the x coordinates (9 in this case) by the ratio (5/1) but that ends up being 45, which seems like waay too much.. :/
@jdoe0001 do you know?
|dw:1391892208448:dw| \(\bf B(3,-1)\qquad Z(12,5)\\ \quad \\ \quad \\ \color{blue}{\cfrac{ZH}{BH}=\cfrac{ratio1}{ratio2}\implies ratio2\cdot ZH=ratio1\cdot BH\quad \textit{dividing by H}\\ \quad \\ ratio2\cdot Z=ratio1\cdot B\implies} 5(12,5)=1(3,-1)\\ \quad \\\qquad \color{blue}{H=\left(\cfrac{\textit{sum of "x" values}}{ratio1+ratio2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{ratio1+ratio2}\right)}\\ \quad \\ \qquad thus\qquad \\ \quad \\ H=\left(\cfrac{(5\cdot 12)+(1\cdot 3)}{1+5}\quad ,\quad \cfrac{(5\cdot 5)+(1\cdot -1)}{1+5}\right)\)
Is there any way you could explain this to me in words? I'm trying to understand but it's a little confusing. Thanks for the answer, though.
is almost the same as doing similarity checks using proportions if you have done similarity checks, then you can see that the ratios "ratio" is being equivaled to the 2 points given
http://www.teacherschoice.com.au/Maths_Library/Analytical%20Geometry/AnalGeom_3.htm <--- not sure if this helps
Thank you, you were very helpful. a lifesaver!
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