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Mathematics 11 Online
OpenStudy (anonymous):

The height of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent?

OpenStudy (anonymous):

The coin falls down with an average speed of 132.3 meters per second from 3 seconds to 6 seconds. The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. The coin travels an average distance of 132.3 meters from 3 seconds to 6 seconds. The coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

OpenStudy (anonymous):

x/t is speed. So the rate of change will be related to speed. At t=3; the coin is falling at 29.4m/s and at t-6; the coin is falling at 58.8m/s.

OpenStudy (anonymous):

If you take these and add them together, then divide by 2, you'll get rate per 3 seconds. Divide by 3 and you get 14.7m/s.

OpenStudy (anonymous):

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