Question

Help? http://prntscr.com/2qqwru

Answer 1

@phi @thomaster @bibby help?

Answer 2

depending on how you want to cancel it, you can cross out the 2's or you can do this\[\frac{2a^5}{7b^4}*\frac{2b^2}{a^4}\]

Answer 3

So would it be like this?\[\frac{ 4a^5b^2 }{ 7a^4b^4 }\]

Answer 4

then we take one more step. recall the property of exponents\[\large \frac{ a^x }{ a^y } = a^{x-y}\]

Answer 5

\(\bf \cfrac{4a^5}{7b^4}\cdot \cfrac{2b^2}{2a^4}\implies \cfrac{4a^52b^2}{7b^42a^4}\implies
\cfrac{4{\color{blue}{ a^4}}a^1{\color{blue}{ 2b^2}}}{7b^2{\color{blue}{ b^2}}{\color{blue}{ 2a^4}}}\)

Answer 6

Ok so then it would be this? \[\frac{ 4 }{ 7 }a^ 9b^ 6\]

Answer 7

not exactly.\[\large \frac{ a^5 }{ a^4 } = a^{5-4}\]

Answer 8

Oh i think i see what i did wrong. It would be
4a
--
7b^2

because you subtract the b exponents and the a exponents right?

Answer 9

exactly.