Please help me with this before midnight?
The wording of this problem is really confusing to me...
http://tinypic.com/r/2con50i/8

This is what I tried to do:
P1= 2.0atm, P2= 6.0atm, V1=V1 and V2=V2
Then I plugged everything in... like this:
(2.0atm)V1=(6.00atm)V2 and since I was trying to find V1, I divided both sides by 2.0atm and came up with:
V1 = 3.0 V2

Question

Please help me with this before midnight? 
The wording of this problem is really confusing to me...
http://tinypic.com/r/2con50i/8

This is what I tried to do: 
P1= 2.0atm, P2= 6.0atm, V1=V1 and V2=V2
Then I plugged everything in... like this:
(2.0atm)V1=(6.00atm)V2 and since I was trying to find V1, I divided both sides by 2.0atm and came up with: 
V1 = 3.0 V2

joannablackwelder · Answer

You are close. When the pressure changes by multiplying by 3, the Volume must change by a factor of 1/3 to keep the same temp and pressure.
At constant T and n, P1V1=P2V2.
So, 2*V1=6*V2 and V2=1/3*V1.

joannablackwelder · Answer

Your calculation is correct, but they wanted you to solve for V2.

joannablackwelder · Answer

They are calling V1, V0. And V2, V1.

anonymous · Answer

Oooohh, that's what was confusing me. Thank you very much for your help :)

joannablackwelder · Answer

No worries. Good job so far! :)