Question

Help with this? http://prntscr.com/2qrrw4 When i did it i factored it and it didnt come out right what am i doing wrong?

Answer 1

@bibby help again? >.< you're probably tired of helping me

Answer 2

I'm actually just rited. I'll go take a nap soon

Answer 3

:P bibby

Answer 4

\[\frac{ (a-3)(a+1) }{ (a-6)(a-3) }-\frac{ (a-3)(a-2) }{ (a+8)(a+1) }\]

Answer 5

I assume you have to multiply one by the denominator of the other, ugh

Answer 6

why would i multiply if it says simplify the difference?

Answer 7

because they're not in a common denominator. you can't subtract\[\frac{ 1 }{ 2 }-\frac{ 1 }{ 3 }\]

just liuke that can you

Answer 8

Oh yea i forgot gosh i overthinking this wayyy too much :/ let me try that and see what i have.

Answer 9

I'll give it a try too bby

Answer 10

\[\large [\frac{ (a-3)(a+1) }{ (a-6)(a-3) }*(a+8)(a+1)]-\frac{ (a-3)(a-2) }{ (a+8)(a+1) }*(a+8)(a+1)\]

\[\large [\frac{ (a-3)(a+1) }{ (a-6)(a-3) }*(a+8)(a+1)]- (a-3)(a-2)\]

Answer 11

this is getting messy, I think I overcomplicated things

Answer 12

\(\bf \cfrac{a^2-2a-3}{a^2-9a+18}-\cfrac{a^2-5a-6}{a^2+9a+8}\\ \quad \\ \quad \\

\cfrac{ \cancel{(a-3)}(a+1) }{ (a-6)\cancel{(a-3)} }-\cfrac{ (a-6)\cancel{(a+1)} }{ (a+8)\cancel{(a+1)} }\)

Answer 13

God... You've saved me yet again @jdoe0001 .

Answer 14

Thanks guys im grateful ♥