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Mathematics 13 Online
OpenStudy (anonymous):

I need help completing the square, please =)

OpenStudy (anonymous):

Only the solutions of g(x) will lead you safely across.

OpenStudy (anonymous):

g(x) = x^2 + 6x + 3

OpenStudy (jdoe0001):

do you know what a "perfect square trinomial" is?

OpenStudy (anonymous):

Pretty much

OpenStudy (anonymous):

Do I have to make it a perfect square trinomial?

OpenStudy (jdoe0001):

\(\bf g(x) = x^2 + 6x + 3\implies g(x) = (x^2 + 6x) + 3\\ \quad \\ g(x) = (x^2 + 6x+{\color{red}{ \square }}^2) + 3\) what do you think we need there to make a "perfect square trinomial"?

OpenStudy (jdoe0001):

yes, "completing the square" really just means, "make it with a perfect square trinomial"

OpenStudy (anonymous):

I believe you divide 6 by 2 then square it, so it would then be g(x) = (x^2 + 6x + 9) + 3?

OpenStudy (anonymous):

And okay

OpenStudy (jdoe0001):

yes... so we ADDED \(3^2\) so we also have to SUBTRACT \(3^2\) as well recall, all we're doing is borrowing from Mr Zero, 0, so 9-9 = 0 and \(\bf x^2 + 6x + 3+0 \implies x^2 + 6x + 3\) so \(\bf g(x) = x^2 + 6x + 3\implies g(x) = (x^2 + 6x) + 3\\ \quad \\ g(x) = (x^2 + 6x+{\color{red}{ 3 }}^2) + 3-{\color{red}{ 3 }}^2\)

OpenStudy (jdoe0001):

\(\bf g(x) = (x^2 + 6x+{\color{red}{ 3 }}^2) + 3-{\color{red}{ 3 }}^2\implies g(x)=(x+3)^2-6\)

OpenStudy (anonymous):

Thank you

OpenStudy (anonymous):

@jdoe0001 , can you help me with one more?

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