How would I solve this for x?
Sine, right?
\[\sin 37^{o}=\frac{18}{x}\]
So do I multiply sin(37) by 18? Or 1/18?
Hello?
\[\sin 37^\circ = \frac{18}x\]You want \(x\) all alone on one side, with everything else on the other. This is no different than solving \[a = \frac{b}{c}\]for \(c\). How would you do that?
So I do multiply by 18?
x=30
No. \[a=\frac{b}{c}\]Multiply both sides by \(c\)\[ac = c*\frac{b}{c}\]\[ac = b\]Divide both sides by \(a\) \[\frac{ac}{a} = \frac{b}{a}\]\[c = \frac{b}{a}\]
When I do that, I get .49
You can just swap \(a\) and \(c\) without doing all the steps once you realize this is what happens. So\[\sin 37^\circ = \frac{18}{x}\]\[x \sin 37^\circ = 18\]\[x = \frac{18}{\sin 37^\circ} \approx 29.91\]
Oops. I just did 18/37, not sin37. My bad. Okay. I get it now. Thanks so much! God bless you!
Make sure your calculator is in degree mode, not radian mode, or you'll get a different (and wrong!) answer.
Why don't you try it, make sure you get the same answer, then you'll know it is in the right mode.
I did. It is. I always get confused on when I need to use which form..
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