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Mathematics 23 Online
OpenStudy (anonymous):

How would I solve this for x?

OpenStudy (anonymous):

OpenStudy (anonymous):

Sine, right?

OpenStudy (mertsj):

\[\sin 37^{o}=\frac{18}{x}\]

OpenStudy (anonymous):

So do I multiply sin(37) by 18? Or 1/18?

OpenStudy (anonymous):

Hello?

OpenStudy (whpalmer4):

\[\sin 37^\circ = \frac{18}x\]You want \(x\) all alone on one side, with everything else on the other. This is no different than solving \[a = \frac{b}{c}\]for \(c\). How would you do that?

OpenStudy (anonymous):

So I do multiply by 18?

OpenStudy (masumanwar):

x=30

OpenStudy (whpalmer4):

No. \[a=\frac{b}{c}\]Multiply both sides by \(c\)\[ac = c*\frac{b}{c}\]\[ac = b\]Divide both sides by \(a\) \[\frac{ac}{a} = \frac{b}{a}\]\[c = \frac{b}{a}\]

OpenStudy (anonymous):

When I do that, I get .49

OpenStudy (whpalmer4):

You can just swap \(a\) and \(c\) without doing all the steps once you realize this is what happens. So\[\sin 37^\circ = \frac{18}{x}\]\[x \sin 37^\circ = 18\]\[x = \frac{18}{\sin 37^\circ} \approx 29.91\]

OpenStudy (anonymous):

Oops. I just did 18/37, not sin37. My bad. Okay. I get it now. Thanks so much! God bless you!

OpenStudy (whpalmer4):

Make sure your calculator is in degree mode, not radian mode, or you'll get a different (and wrong!) answer.

OpenStudy (whpalmer4):

Why don't you try it, make sure you get the same answer, then you'll know it is in the right mode.

OpenStudy (anonymous):

I did. It is. I always get confused on when I need to use which form..

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