Question

Please explain the steps you take.
Simplify
https://media.glynlyon.com/g_alg01_2013/8/test14.gif

Answer 1

\[\frac{y}{\sqrt{y}}=\frac{y\sqrt{y}}{\sqrt{y}\sqrt{y}}=\frac{y\sqrt{y}}{y}=\frac{\cancel y\sqrt{y}}{\cancel y}=\sqrt{y}\]

Answer 2

by exactly the same method you get \(\frac{\sqrt 6}{6}=\frac{1}{\sqrt 6}\)

Answer 3

so it would be \[\frac{ 1 }{ \sqrt{6y}}\]

Answer 4

no, the \(\sqrt{y}\) is in the numerator

Answer 5

ohhhh, ok. that makes more sense.

Answer 6

you can write it as \(\frac{\sqrt{y}}{\sqrt{6}}\) or
\[\sqrt{\frac{y}{6}}\]
i am not sure what "simplify" means in this context

Answer 7

ok, I have options if you wanna see. I don't know what sense it would make though, since you already know the answer :) haha I have a question though :)

Answer 8

when you said "\frac{y}{\sqrt{y}}=\frac{y\sqrt{y}}{\sqrt{y}\sqrt{y}}=\frac{y\sqrt{y}}{y}=\frac{\cancel y\sqrt{y}}{\cancel y}=\sqrt{y}" why did you put \[\sqrt {y}\] on the numerator and denominator

Answer 9

\[\frac{y}{\sqrt{y}}=\frac{y\sqrt{y}}{\sqrt{y}\sqrt{y}}=\frac{y\sqrt{y}}{y}=\frac{\cancel y\sqrt{y}}{\cancel y}=\sqrt{y}\]

Answer 10

the \(y\)'s cancel top and bottom

Answer 11

what i mean by this is simply that\[\frac{\sqrt{a}}{a}=\sqrt{a}\] always
for example
\[\frac{\sqrt{5}}{5}=\sqrt{5}\]

Answer 12

Oh ok, Thanks for the help :)