Question

I'm asking this for a friend... What is the ionic equation for NaF(aq) and AgNO3(aq)?
We came up with Na+(aq) + F-(aq) + Ag+(aq) + NO3-(aq) --> AgF(s) + Na+(aq) + NO3+(aq)
However, our online homework program said it was incorrect...
Please tell us what's wrong?

Answer 1

Is Ag+ or Ag++ and is NO3- or NO3-- ?

Answer 2

The problem doesn't specify...
I assumed that Ag is + and NO3 is -

Answer 3

Look at where Ag is on the periodic table. Na and K become Na+ and K+, but Ag is not in their column. If Ag is Ag++ and No3_ is correct, then you would need two NO3- for every one Ag++. Don't have my chem book at hand.

Answer 4

Ah, okay, thanks ^ ^

Answer 5

If AgNO3 is the right formula, then Ag will have as many + as NO3 has -