Question

Bohrium-267 has a half-life of 15 seconds. Find the amount that remains from a 16 mg sample of this substance after 2 minutes.
f(x)=p*a^x

Answer 1

Easy when dealing with multiples of half-lift times.
120 s / 15 s = 8

fraction remaining is (1/2)^8 = 1/256
amount is this fraction times starting amount.

Answer 2

huh . lol im confussed

Answer 3

15 seconds 1/2
30 seconds 1/4
45 seconds 1/8
60 seconds 1/16
75 seconds 1/32
90 seconds 1/64
...

Getting the idea?

Answer 4

Lol not really .

Answer 5

Good explanation.

Answer 6

i have to fill that in .