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Mathematics 17 Online
OpenStudy (anonymous):

What formula do i use to get the answer?

OpenStudy (anonymous):

OpenStudy (anonymous):

1. For the right triangular prism below: A) Find the length of side d.

OpenStudy (anonymous):

I dont know what formula i use to find the length?

OpenStudy (whpalmer4):

Well, isn't the end of that a right triangle, where we know the two sides, and need to find the hypotenuse? Do you know any theorems that would help us to do that?

OpenStudy (anonymous):

I know how to caculate surface area volume etc.

OpenStudy (anonymous):

Which end?

OpenStudy (anonymous):

Are you talking about the elngth of c=12

OpenStudy (anonymous):

Length*

OpenStudy (whpalmer4):

the end that has side d as part of it |dw:1391916194415:dw|

OpenStudy (anonymous):

Isnt it the hypotenuse formula

OpenStudy (anonymous):

The missing length?

OpenStudy (anonymous):

Isnt their a formula so i can find that missing length

OpenStudy (whpalmer4):

Yes. What is the value of d?

OpenStudy (anonymous):

I dont know

OpenStudy (whpalmer4):

Use the Pythagorean theorem. Do you remember it?

OpenStudy (anonymous):

I do not, can you plz remind me?

OpenStudy (whpalmer4):

In a right triangle with sides \(a\), \(b\) and hypotenuse \(c\), \[a^2+b^2=c^2\]

OpenStudy (anonymous):

Ok let me right it on paper

OpenStudy (anonymous):

One second.

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Got it written

OpenStudy (anonymous):

Do i feel in the variables with the information given?

OpenStudy (whpalmer4):

yes.

OpenStudy (anonymous):

Ok i am doing it on paper

OpenStudy (anonymous):

One second let me get a tissue real quick i am sick.

OpenStudy (whpalmer4):

I'm not going anywhere

OpenStudy (anonymous):

Thank you.

OpenStudy (anonymous):

Alright i got it filled in.

OpenStudy (anonymous):

So let me do the powers.

OpenStudy (anonymous):

Ok i got this 64+36=144

OpenStudy (anonymous):

a^2+b^2=c^ 8^+6^=12^2 64+36=144

OpenStudy (anonymous):

Thats how i got it

OpenStudy (anonymous):

You there?

OpenStudy (whpalmer4):

okay, so what is the value of \(d\)?

OpenStudy (anonymous):

Uhhh

OpenStudy (anonymous):

Since i got 64+36=144 what do i do now?

OpenStudy (anonymous):

I get 100=144

OpenStudy (anonymous):

Then i kinda stuck right here?

OpenStudy (whpalmer4):

That's the tip-off that your arithmetic needs some work :-) \[a^2+b^2=c^2\]We know \(a = 8\) and \(b=6\): \[8^2+6^2 = c^2\]\[64+36 = c^2\] what is \(64+36=\)?

OpenStudy (anonymous):

Ohhh ok but when you look at the picture i gave you it says c equals 12?

OpenStudy (anonymous):

Since its a prism

OpenStudy (anonymous):

Do i include that or i just concertrate on A,B,D

OpenStudy (anonymous):

64+36=10,000

OpenStudy (whpalmer4):

ah, you're being confused by the labeling on that diagram. Ignore it. We are only talking about this triangle, and for our purposes, the hypotenuse is called \(c\)

OpenStudy (whpalmer4):

64+36=10,000?!?

OpenStudy (anonymous):

Yeah, cause c^2 power right?

OpenStudy (whpalmer4):

here I always thought 64+36 = 100

OpenStudy (anonymous):

I think i got confuse cause the formula said c^2

OpenStudy (anonymous):

So 100*100 is 10,000

OpenStudy (anonymous):

But if i got 100 so my length would be 100 O:

OpenStudy (whpalmer4):

no. look at what I wrote: \[a^2+b^2=c^2\]\[8^2+6^2=c^2\]\[64+36=c^2\]\[100=c^2\]\[c=\]

OpenStudy (anonymous):

Ohhhh

OpenStudy (anonymous):

What happen to the 100?

OpenStudy (anonymous):

c=0?

OpenStudy (anonymous):

Did you do 100=c^2 - c^2

OpenStudy (anonymous):

Im comfused O:

OpenStudy (whpalmer4):

if \[100=c^2\]what does \(c =\) ?

OpenStudy (anonymous):

Uhhhhh...

OpenStudy (whpalmer4):

what number \(c\) satisifies \(c*c = 100\)?

OpenStudy (anonymous):

10?

OpenStudy (anonymous):

Oh ok i get what you did :P

OpenStudy (whpalmer4):

yes! so the hypotenuse of that triangle with sides a = 8 and b = 6 is length 10. they labeled it "d" in the diagram.

OpenStudy (anonymous):

Ok let me explain it to you and tell me if i get it XD

OpenStudy (anonymous):

Alright so when we got to the part 100= c^2

OpenStudy (anonymous):

what did you do to get 10 thats what i am comfused about

OpenStudy (anonymous):

Did you put a number and see what fit 100 evenly?

OpenStudy (anonymous):

Kinda like trial and error

OpenStudy (whpalmer4):

Well, I just know that 10*10 = 100, so I would write down c=10 without thinking. But what I did is take the square root of both sides: \[c^2= 100\]\[\sqrt{c^2} = \sqrt{100}\]\[c = \sqrt{100} = 10\]

OpenStudy (anonymous):

Ahhhhhhhhh

OpenStudy (anonymous):

Ok i see now

OpenStudy (whpalmer4):

Good. so that's the first part of the problem, right?

OpenStudy (anonymous):

Can you hold on one second let me see if i can do it on paper.

OpenStudy (anonymous):

Yeah i did it!

OpenStudy (anonymous):

Ok but when you say this is the first part of the problem whats the second part O:

OpenStudy (whpalmer4):

well, the picture asks us to find the base area, does it not?

OpenStudy (anonymous):

Well yes it does O:

OpenStudy (anonymous):

But before we continue

OpenStudy (anonymous):

What is the formula i used called?

OpenStudy (whpalmer4):

the Pythagorean theorem

OpenStudy (anonymous):

Ok, Let me take notes

OpenStudy (anonymous):

And one more question on this formula

OpenStudy (anonymous):

Why didnt i apply 12 to c^2

OpenStudy (anonymous):

Is it because if i would write it i would write it as such a^2+b^2=d^2

OpenStudy (anonymous):

Because d is the missing length

OpenStudy (whpalmer4):

yes. the letters are just symbols or placeholders. the Pythagorean theorem still works no matter what letters you use: <length of 1 side>^2 + <length of 2nd side>^2 = <length of hypotenuse>^2

OpenStudy (anonymous):

Ok good, because it was c i thought it wanted me to apply 12 cause it said c

OpenStudy (anonymous):

But like you said palce holder

OpenStudy (anonymous):

place*

OpenStudy (anonymous):

Writing notes.

OpenStudy (anonymous):

and when you fliped them what property did you use?

OpenStudy (whpalmer4):

what, you mean when I did\[10 = c\]\[c=10\]? or what?

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