Question

What is x in 2sinxcosx+2sinx-cosx-1=0

Answer 1

2sinxcosx+2sinx-cosx-1=0
\[2\sin(x)\cos(x)+2\sin(x)-\cos(x)-(\sin^2(x)+\cos^2(x))=0\]
Now divide by cos^2(x) on both sides of the equation.
Simplify to get a quadratic equation in tan(x).
I think the rest is obvious.

Note that by dividing with cos^2(x) we implicitly assumed that cos^2(x) ≠ 0
So we need to solve 2sinxcosx+2sinx-cosx-1=0 separately for cos^2(x) = 0

Answer 2

Aah..It can be easily factorized..that makes life a lot easier ;)

Answer 3

@surjithayer
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