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Use the identity cos(alpha-beta)=cos(alpha)cos(beta)+sin(alpha)sin(beta) to find cos(5pi/12)
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Wouldn't that be cos(alpha-beta)=cos(alpha)cos(beta)+sin(alpha)sin(beta), and not cos(alpha-beta)=cos(alpha)cos(beta)+sin(alpha)+sin(beta)?
Yes it would be
Think of two angles whose difference is 5pi/12, and one of which is an angle whose sine and cosine are easy to remember/evaluate.
11pi-6pi??
Divide both of those by 12, so that the resulting difference will be 5pi/12.
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