A rock dropped from ad cliff hits the ground 2.5 seconds later. Another rock thrown horizontally from the same cliff lands 20 m from the bad of the cliff. What was the thrown rock's initial speed?
The horizontal and vertical motions of the rock are independent. The second rock is thrown horizontally - thus its falling down vertically will be equivalent to the first rock. Since in both cases, the rocks have Zero initial horizontal velocity when released. Right?
Yes exactly sir
Thus both the rocks will hot the ground in the SAME amount of time. Right?
Yes sir that is true
The second rock will thus hit the ground after 2.5 seconds.
Yes since they will fall at the same time right?
Right. So now can we find the horizontal speed of the second rock? It falls 20 mts away from the cliff edge. In 2.5 seconds.
But sir how would you find the length of the cliff?
Don't you need that?
We dont need to know that right? We KNOW that: 1. In 2.5 seconds the second rock travelled 20 mts in the horizontal direction; 2. The force of Gravity acts only in the vertical direction - there is NO FORCE in the horizontal direction.
Oh ok sir so then you would just substitute 20 for d if you were using d=vt?
Yes. Exactly. That will give you "v" - the horizontal velocity.
Thank you so much sir
Welcome! So v=8 m/s - just to confirm.
Yes sir
Thank you sir
Join our real-time social learning platform and learn together with your friends!