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Physics 19 Online
OpenStudy (anonymous):

A rock dropped from ad cliff hits the ground 2.5 seconds later. Another rock thrown horizontally from the same cliff lands 20 m from the bad of the cliff. What was the thrown rock's initial speed?

OpenStudy (anonymous):

The horizontal and vertical motions of the rock are independent. The second rock is thrown horizontally - thus its falling down vertically will be equivalent to the first rock. Since in both cases, the rocks have Zero initial horizontal velocity when released. Right?

OpenStudy (anonymous):

Yes exactly sir

OpenStudy (anonymous):

Thus both the rocks will hot the ground in the SAME amount of time. Right?

OpenStudy (anonymous):

Yes sir that is true

OpenStudy (anonymous):

The second rock will thus hit the ground after 2.5 seconds.

OpenStudy (anonymous):

Yes since they will fall at the same time right?

OpenStudy (anonymous):

Right. So now can we find the horizontal speed of the second rock? It falls 20 mts away from the cliff edge. In 2.5 seconds.

OpenStudy (anonymous):

But sir how would you find the length of the cliff?

OpenStudy (anonymous):

Don't you need that?

OpenStudy (anonymous):

We dont need to know that right? We KNOW that: 1. In 2.5 seconds the second rock travelled 20 mts in the horizontal direction; 2. The force of Gravity acts only in the vertical direction - there is NO FORCE in the horizontal direction.

OpenStudy (anonymous):

Oh ok sir so then you would just substitute 20 for d if you were using d=vt?

OpenStudy (anonymous):

Yes. Exactly. That will give you "v" - the horizontal velocity.

OpenStudy (anonymous):

Thank you so much sir

OpenStudy (anonymous):

Welcome! So v=8 m/s - just to confirm.

OpenStudy (anonymous):

Yes sir

OpenStudy (anonymous):

Thank you sir

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