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Physics 23 Online
OpenStudy (anonymous):

A sprinter accelerates from rest to 8.50 m/s in 1.40s. What is her acceleration in m/s^2?

OpenStudy (joannablackwelder):

Acceleration = velocity/elapsed time

OpenStudy (anonymous):

Whats her acceleration in km/h^2

OpenStudy (joannablackwelder):

Convert m/s to km/hr and s to hr before you plug into the formula.

OpenStudy (anonymous):

How I would convert them ?

OpenStudy (anonymous):

1.40 seconds multiplied by 1 hour over 3600 seconds

OpenStudy (anonymous):

Can I get the final answer

OpenStudy (roadjester):

\[{8.50m\over s}X {1km\over 1000m } X {3600s\over 1hr}\] \[1.40s X{1hr\over 3600s}\] notice how the units cancel

OpenStudy (joannablackwelder):

Right. You want to use an equality as a fraction to cancel out the unit you don't want and leave you with the unit you do want.

OpenStudy (joannablackwelder):

No, but if you calculate it, I will tell you if it is right or wrong.

OpenStudy (anonymous):

I got 2.190721649

OpenStudy (anonymous):

is this right?

OpenStudy (anonymous):

7.87x10^4?

OpenStudy (joannablackwelder):

I get the second one you posted. 7.87 x 10^4 km/hr^2

OpenStudy (anonymous):

Calculate the average speed of a complete round trip in which the outgoing 210km is covered at 98km/h , followed by a 1.0-h lunch break, and the return 210km is covered at 52km/h .

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