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Physics 8 Online
OpenStudy (anonymous):

A particle's position as a function of time t is given by r⃗ =(5.0t+6.0t2)mi+(7.0−3.0t3)mj. At t=5.0s, find the magnitude of the particle's displacement vector Δr⃗ relative to the point r⃗ 0=(0.0i+7.0j)m. At t=5.0s, find the angle of the particle's displacement vector Δr⃗ relative to the point r⃗ 0=(0.0i+7.0j)m.

OpenStudy (roadjester):

do you know the distance formula from geometry?

OpenStudy (anonymous):

A particle's position as a function of time t is given by r⃗ =(5.0t+6.0t2)mi^+(7.0−3.0t3)mj^

OpenStudy (roadjester):

the distance between two points the phrase "relative to", think of that as one point. so for the first one it's (0,7). Substitute t=5 into your first displacement function to get your second point. so now you have a second (x,y) coordinate. then use the distance formula

OpenStudy (roadjester):

the word "magnitude" just means distance or length

OpenStudy (anonymous):

i got it! thanks!

OpenStudy (roadjester):

uh huh no prob

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