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Mathematics 15 Online
OpenStudy (anonymous):

Verify the identity. cot θ ∙ sec θ = csc θ

OpenStudy (anonymous):

I'm not exactly sure what it's asking me to do

OpenStudy (campbell_st):

ok... so cot = 1/tan and tan = sin/cos which means cot = cos/sin and sec = 1/cos so substitute cot = cos/sin and sec = 1/cos and you get \[\frac{\cos(x)}{\sin(x)} \times \frac{1}{\cos(x)} \] cancel the common factor and you're left with \[\frac{1}{\sin(x)}\] so how do you think csc(x) can be written using sin, cos or tan..?

OpenStudy (anonymous):

I really have no idea

OpenStudy (anonymous):

@ganeshie8 Can you help me please?

OpenStudy (jdoe0001):

\(\bf {\color{blue}{ cot(\square )=\cfrac{cos(\square )}{sin(\square )}\qquad \qquad sec(\square )=\cfrac{1}{cos(\square )}}}\\ \quad \\ \quad \\ cot(\theta)\cdot sec(\theta)=csc(\theta)\\ \quad \\ \implies \cfrac{cos(\theta )}{sin(\theta )}\cdot \cfrac{1}{cos(\theta )}\)

OpenStudy (anonymous):

So would this be the final answer?

OpenStudy (jdoe0001):

well... what did you get?

OpenStudy (jdoe0001):

can you simplify it further?

OpenStudy (anonymous):

Do I put that in my calc?

OpenStudy (jdoe0001):

well, you're just expected to make the LEFT-SIDE look like the RIGHT-SIDE, is all

OpenStudy (anonymous):

Ohhhh okay. Thank you!

OpenStudy (jdoe0001):

yw

OpenStudy (anonymous):

And if I'm correct csc θ = 1/sinθ

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