Question

The variation of H2SO4 specific heat due tp temperature with unitis of cal.mol-1.°C-1is given by equation:
Cp=33.25+0.033.T
Were T is in °C
Changing the equation so the new units of Cp are
cal.mol-1.K-1 the new equation is:

(A) Cp= 297,241 + 9,009 .T
(B) Cp= 297,241 + 0,033 .T
(C) Cp= 24,241 + 9,009 .T
(D) Cp= 24,241 + 0,033 .T
(E) Cp= 33,25 + 9,009 .T

Answer 1

@experimentX

Answer 2

just shift the equation by right ... by 273

Answer 3

x -> x - 273

Answer 4

the ans is B

Answer 5

http://www.wolframalpha.com/input/?i=Plot%5B33.25%2B0.033%28T-273%29+%2C+%7BT%2C+0%2C+100%7D%5D

Answer 6

but how you get B??

Answer 7

http://www.wolframalpha.com/input/?i=33.25%2B0.033%28x-273%29

Answer 8

but that is not the answer

Answer 9

as far as i understand, the Cp is given as function of temperature on scale of Celcius. now you want to change it into Kelvin scale.

at T=0 at C and T=273 at K, both must have same value.

Answer 10

i dont think they must have same value since they are not in same unit

1m = 100cm but 1 isn't equal to 100

Answer 11

Cp=33.25+0.033.T
how do you define this at C scale at 0 C?

Answer 12

33.25[cal/(mol.°C)]

Answer 13

this is not equal to 33.25[cal/(mol.K)]

Answer 14

it means that if you heat a mole of that acid, it will take 33.25 cal of energy for rise in temp.
use the same def for kelvin scale.

Answer 15

ok, so the ans is wrong?

Answer 16

http://www.asknumbers.com/HeatCapacityConversion.aspx
probably

Answer 17

thanks