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Physics 8 Online
OpenStudy (anonymous):

Could someone explain how to solve projectile motion problems?

OpenStudy (roadjester):

Movement in the horizontal and vertical directions are independent of each other so you want to use sine and cosine to break up vectors into their components.

OpenStudy (anonymous):

I don't get this concept at all

OpenStudy (roadjester):

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OpenStudy (anonymous):

The problems related to this are had

OpenStudy (anonymous):

Hard*

OpenStudy (roadjester):

ok, so force is a vector. moving up does not affect moving right. so to calculate the direction moving right you use F cos theta. For upward motion you use F sin theta

OpenStudy (anonymous):

Is this high school level physics?

OpenStudy (roadjester):

vectors? it's high school math. You're just applying it in physics. What grade are you in?

OpenStudy (anonymous):

9

OpenStudy (roadjester):

If you've taken calculus or are taking it, it would help immensely. if not, you'll get there

OpenStudy (anonymous):

Ok can I ask a question from my physics book?

OpenStudy (roadjester):

sure,

OpenStudy (anonymous):

A bowling ball is moving at 10m/s when it rolls off the edge of a tall building. What is the ball'sspeed one second later?

OpenStudy (roadjester):

19.8 m/s?

OpenStudy (anonymous):

How did you calculate that?

OpenStudy (roadjester):

\[v_f = v_i +at\] a=9.8m/s^2

OpenStudy (anonymous):

What are vf and vi in this equation?

OpenStudy (roadjester):

initial and final velocity

OpenStudy (anonymous):

So what do you use this formula for in physics

OpenStudy (roadjester):

kinematics

OpenStudy (anonymous):

Ok thanks

OpenStudy (anonymous):

So how do u find the time?

OpenStudy (roadjester):

it was given

OpenStudy (anonymous):

Oh nvm

OpenStudy (joannablackwelder):

I get a different answer. Time is given in the problem. 1 sec

OpenStudy (anonymous):

What answer did u get?

OpenStudy (anonymous):

I got 19.8 m/s

OpenStudy (joannablackwelder):

Horizontal speed will stay constant because no acceleration is acting on it.

OpenStudy (anonymous):

Right

OpenStudy (joannablackwelder):

Vertical velocity is what changes using the formula given earlier.

OpenStudy (anonymous):

So what is the formula?

OpenStudy (joannablackwelder):

The initial velocity in the vertical direction is 0, acceleration is -9.8 m/s^2 and time is. 1.

OpenStudy (anonymous):

It could be

OpenStudy (joannablackwelder):

So, the final velocity in the vertical direction is -9.8 m/s.

OpenStudy (anonymous):

Is it ok if its negative?

OpenStudy (joannablackwelder):

Using the pythagorean theorem to find the resultant velocity gives 14 m/s.

OpenStudy (joannablackwelder):

Yes, negative just means downward.

OpenStudy (anonymous):

Which 2 numbers did you use to find the resultant?

OpenStudy (joannablackwelder):

10 m/s and -9.8 m/s.

OpenStudy (anonymous):

So which solution is right?

OpenStudy (joannablackwelder):

Have you studied vectors yet?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

But I don't get them fully

OpenStudy (joannablackwelder):

Then, I think that my solution is probably the way you are supposed to work the problem.

OpenStudy (roadjester):

I'm assuming 24 m/s? I haven't studied kinematics in a while

OpenStudy (joannablackwelder):

You can only use projectile motion equations in the horizontal and vertical directions separately.

OpenStudy (joannablackwelder):

Then connect them back together using right triangles.

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