Could someone explain how to solve projectile motion problems?
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OpenStudy (roadjester):
Movement in the horizontal and vertical directions are independent of each other so you want to use sine and cosine to break up vectors into their components.
OpenStudy (anonymous):
I don't get this concept at all
OpenStudy (roadjester):
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OpenStudy (anonymous):
The problems related to this are had
OpenStudy (anonymous):
Hard*
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OpenStudy (roadjester):
ok, so force is a vector. moving up does not affect moving right. so to calculate the direction moving right you use F cos theta.
For upward motion you use F sin theta
OpenStudy (anonymous):
Is this high school level physics?
OpenStudy (roadjester):
vectors? it's high school math. You're just applying it in physics. What grade are you in?
OpenStudy (anonymous):
9
OpenStudy (roadjester):
If you've taken calculus or are taking it, it would help immensely. if not, you'll get there
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OpenStudy (anonymous):
Ok can I ask a question from my physics book?
OpenStudy (roadjester):
sure,
OpenStudy (anonymous):
A bowling ball is moving at 10m/s when it rolls off the edge of a tall building. What is the ball'sspeed one second later?
OpenStudy (roadjester):
19.8 m/s?
OpenStudy (anonymous):
How did you calculate that?
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OpenStudy (roadjester):
\[v_f = v_i +at\]
a=9.8m/s^2
OpenStudy (anonymous):
What are vf and vi in this equation?
OpenStudy (roadjester):
initial and final velocity
OpenStudy (anonymous):
So what do you use this formula for in physics
OpenStudy (roadjester):
kinematics
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OpenStudy (anonymous):
Ok thanks
OpenStudy (anonymous):
So how do u find the time?
OpenStudy (roadjester):
it was given
OpenStudy (anonymous):
Oh nvm
OpenStudy (joannablackwelder):
I get a different answer. Time is given in the problem. 1 sec
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OpenStudy (anonymous):
What answer did u get?
OpenStudy (anonymous):
I got 19.8 m/s
OpenStudy (joannablackwelder):
Horizontal speed will stay constant because no acceleration is acting on it.
OpenStudy (anonymous):
Right
OpenStudy (joannablackwelder):
Vertical velocity is what changes using the formula given earlier.
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OpenStudy (anonymous):
So what is the formula?
OpenStudy (joannablackwelder):
The initial velocity in the vertical direction is 0, acceleration is -9.8 m/s^2 and time is. 1.
OpenStudy (anonymous):
It could be
OpenStudy (joannablackwelder):
So, the final velocity in the vertical direction is -9.8 m/s.
OpenStudy (anonymous):
Is it ok if its negative?
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OpenStudy (joannablackwelder):
Using the pythagorean theorem to find the resultant velocity gives 14 m/s.
OpenStudy (joannablackwelder):
Yes, negative just means downward.
OpenStudy (anonymous):
Which 2 numbers did you use to find the resultant?
OpenStudy (joannablackwelder):
10 m/s and -9.8 m/s.
OpenStudy (anonymous):
So which solution is right?
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OpenStudy (joannablackwelder):
Have you studied vectors yet?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
But I don't get them fully
OpenStudy (joannablackwelder):
Then, I think that my solution is probably the way you are supposed to work the problem.
OpenStudy (roadjester):
I'm assuming 24 m/s? I haven't studied kinematics in a while
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OpenStudy (joannablackwelder):
You can only use projectile motion equations in the horizontal and vertical directions separately.
OpenStudy (joannablackwelder):
Then connect them back together using right triangles.