A plane bisects a 90 degrees dihedral angle. From a point on this plane 16 in. From the common edge, perpendicular lines are constructed to the respected faces of the dihedral angel find the length of each perpendicular
If we cut the dihedral with a plane perpendicular to the edge, we obtain a 90 degrees angle cut by its bisecting line. **The distances from the points of the planes are the same as the distances from the points of the lines in the normal section.** **All the points of the bisecting line are equidistant from the sides, and the perpendiculars to the sides form two congruent right isosceles triangles. **So, since the the point if 16 inches away from the vertex, you would solve this equation: 16 / √2 = your answer
Hi mangorox, Thanks for the reply. My answer is 8 √2 in. What i did is divide 16 by half and using the pythagorean √8^2 + 8^2 = 8√2 in
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