Question

PLEASE HELP!!!!!
Input in standard form the equation of the given line.

The line that passes through (1, 1) and (3, 4)

Answer 1

Ok, you need to know that the standard for is \[y=mx+c\]where m is the gradient of the line and c the y-intercept.
There's a formula to find the gradient:
\[m=\frac{ y _{2}-y_{1}}{ x _{2}-x_{1} }\]
After you've found the gradient, you simply need to pick a point, say (1,1) and input in the standard form equation the values you have for y, x and m and solve the equation to find c.

Answer 2

could you show the work to me?

Answer 3

No, but I can show you the work for a made up example (:
Find the equation of the line going through the points (1,2) and (2,6).

Okay so we know we're dealing with a straight line, so the equation will have the form y=mx+c

Now let's find m:
we know the equation
m=(y2-y1)/(x2-x1)
So let's input our values:
m=(6-2)/(2-1)
m=4/1
m=4

Great we found m!
Now let's find c.
We know the line goes through the point (1,2) so the equation must hold true when x=1 and y=2;
We know y=mx+c
From what I just said we can write
2=1m+c
We found m earlier
2=4+c
c=2-4
c=-2

The equation of the line is therefore
y=4x-2

Answer 4

The easiest formula for the equation of a straight line, when the slope is known and one or two of the points is/are known, is \[y-y _{0}=m(x-x _{0}).\] I'd suggest that you do this first. Then, re-write this equation in the form y=mx + c, as Quantal has suggested.

Answer 5

OK,thanks guys.this really helped:)