Question

I really need help on this question. I have exhausted all of my options... I do not just want an answer I would like it explained to me.

Which of the following statements have the same result? Explain each step in solving each one.

f(1) when f(x) = 5x + 1
f-1(3) when f(x) = "2x plus 3, all over 5
3y - 7 = y + 5

Answer 1

f-1(3) when f(x) = "2x plus 3, all over 5 is a bit ambiguous. Did you mean the inverse function,
\[f ^{-1}(3) = \frac{ 2x+3 }{ 5 }?\]

Answer 2

Ensure that nothing is missing from your typing in the problem statement and possible answers.

Answer 3

Yes that is what I meant. Sorry.

Answer 4

Everything else is correct. I apologize.

Answer 5

f(1) when f(x) = 5x + 1 is relatively easy. Just substitute 1 for x on the right side of this equation.
3y - 7 = y + 5 can be solved for y. What would be the resulting value of y?
The remaining relationship is problematic because on one hand, you're stating that x=5 on the left side, and on the other hand x has not been replaced with 5. I'd double-check that you've typed this relationship correctly.

Hint: Try solving for f(1) in the first line.
Then try solving for y in the second line.
What do you see?

Answer 6

Okay so for the first one I got 6....

Answer 7

and for the other one I typed it correctly... but I am sort of confused on how I set this one up to solve it: 3y-7=y+5...

Answer 8

Oh wait, it is just simple algebra... that one is also 6..

Answer 9

@mathmale ... can you please explain to me how to do \[f^-1(3)=(2x+3)/(5)\]

Answer 10

The last problem really is not a solvable problem. Note how you obtained 6 for each of the first two. What does that tell you about the answer for this question?

Answer 11

That those two have the same result. So that would be the answer. And then I just explain how to do them.

Answer 12

Thank you so much! (: I guess I knew how to do it, I just needed to be pointed in the right direction.

Answer 13

:)