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(3/4)^x=(16/9)
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Use log to find the x : Suppose : \[a ^{x} = b\] \[\log_{a} b = x\] Now following that we get, \[\log_{3/4} 16/9 = x\] Put that in your calculator and you will get x = -2 answer :)
\(\bf \left(\cfrac{3}{4}\right)^x=\cfrac{16}{9}\implies \cfrac{3^x}{4^x}=\cfrac{16}{9}\qquad recall\implies {\color{blue}{ 16\implies 4^2\qquad 9\implies 3^2}}\)
but the answer is -2 not 2 jdoe
In this one we are actually supposed to solve without using logs.
but you are correct the answer is -2 not 2, I'm not sure I understand why though, is it because we are working with fractions?
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well... ahemm I didn't say it was 2, I just pointed out the values
so is it negative because of the fraction?
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