Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Help reciprocal functions and holes?

OpenStudy (anonymous):

I need to find: a) Excluded values b) y intercept c) x intercept d) horizontal asymptote e) vertical asymptote f) holes

OpenStudy (anonymous):

for the following: f(x) \[(x^2+x-6)/(-4x^2-16x-12)\]

OpenStudy (anonymous):

I got up to: a) -1, -3 b) (0, 1/2) c) (2,0) (-3,0) ??? what happens with the hole? is it an x int? or not? d) (0, -1/4) e) x=-1, x=-3??? f) the hole is (-3, -5/8)

OpenStudy (tkhunny):

A zero in the denominator is a vertical asymptote UNLESS it is also a zero of the numerator. Show numerator and denominator factored completely. We can talk from there.

OpenStudy (anonymous):

i got to the part where it's: (x+3)(x-2)/-4(x+1)(x+3)

OpenStudy (anonymous):

and the x+3 would cancel out

OpenStudy (anonymous):

making it (x-2)/-4(x+1)

OpenStudy (tkhunny):

Don't be so cancel happy. We may need that information. a) Excluded values From the Denominator x = -1 and x = -3 You have this, but your notation could use some improvement. b) y intercept (0,1/2) Substituting x = 0. Very good. c) x intercept The numerator suggests (2,0). You are done, here. You may be tempted to write (-3,0), but don't do it. Look at part a. x = -3 is already excluded. d) horizontal asymptote The horizontal asymptote is an equation of a line. You have a point. Had you written y = -1/4, you would have been correct. e) vertical asymptote x = -1. very good. You are done, here. Again, you may be tempted to write x = -3, but don't do it. Look at part a. x = -3 is already excluded. f) holes Pretty obviously that annoying x = -3 and wherever it would land on the reduced version.

OpenStudy (anonymous):

Thank you very much!!

OpenStudy (tkhunny):

The important thing to remember is that the reduced function and the original function are EXACTLY the same EXCEPT for x = -3. They differ in that one place.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!