Help reciprocal functions and holes?
I need to find: a) Excluded values b) y intercept c) x intercept d) horizontal asymptote e) vertical asymptote f) holes
for the following: f(x) \[(x^2+x-6)/(-4x^2-16x-12)\]
I got up to: a) -1, -3 b) (0, 1/2) c) (2,0) (-3,0) ??? what happens with the hole? is it an x int? or not? d) (0, -1/4) e) x=-1, x=-3??? f) the hole is (-3, -5/8)
A zero in the denominator is a vertical asymptote UNLESS it is also a zero of the numerator. Show numerator and denominator factored completely. We can talk from there.
i got to the part where it's: (x+3)(x-2)/-4(x+1)(x+3)
and the x+3 would cancel out
making it (x-2)/-4(x+1)
Don't be so cancel happy. We may need that information. a) Excluded values From the Denominator x = -1 and x = -3 You have this, but your notation could use some improvement. b) y intercept (0,1/2) Substituting x = 0. Very good. c) x intercept The numerator suggests (2,0). You are done, here. You may be tempted to write (-3,0), but don't do it. Look at part a. x = -3 is already excluded. d) horizontal asymptote The horizontal asymptote is an equation of a line. You have a point. Had you written y = -1/4, you would have been correct. e) vertical asymptote x = -1. very good. You are done, here. Again, you may be tempted to write x = -3, but don't do it. Look at part a. x = -3 is already excluded. f) holes Pretty obviously that annoying x = -3 and wherever it would land on the reduced version.
Thank you very much!!
The important thing to remember is that the reduced function and the original function are EXACTLY the same EXCEPT for x = -3. They differ in that one place.
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