Integral of square root of 2x+1??

Question

nincompoop · Answer

I guess you didn't learn anything for your post earlier?

anonymous · Answer

Oh I must've not seen it

nincompoop · Answer

the rule is that 
integral x^n dx = [x^(n+1)]/(n+1) + C

nincompoop · Answer

and have you learned about integration by substitution yet?

anonymous · Answer

I have but I struggle with square root problems, I kind of blank out on what my next move should be.

nincompoop · Answer

square root of x  is written in exponent form  x^(1/2)

nincompoop · Answer

but it is not as straight-forward in this case since you have sqrt(2x+1) 
if you remember in differentiation, you use chain rule, here you will be using substitution

nincompoop · Answer

so by substitution
 we will make 2x+1 = u; and u' = 2 dx
our new integral would be 
1/2 integral of sqrt(u) du

can you do the rest?

anonymous · Answer

I can! Thank you so much :)