Question

Integral of square root of 2x+1??

Answer 1

I guess you didn't learn anything for your post earlier?

Answer 2

Oh I must've not seen it

Answer 3

the rule is that
integral x^n dx = [x^(n+1)]/(n+1) + C

Answer 4

and have you learned about integration by substitution yet?

Answer 5

I have but I struggle with square root problems, I kind of blank out on what my next move should be.

Answer 6

square root of x is written in exponent form x^(1/2)

Answer 7

but it is not as straight-forward in this case since you have sqrt(2x+1)
if you remember in differentiation, you use chain rule, here you will be using substitution

Answer 8

so by substitution
we will make 2x+1 = u; and u' = 2 dx
our new integral would be
1/2 integral of sqrt(u) du

can you do the rest?

Answer 9

I can! Thank you so much :)