Question

phase change

Answer 1

1a)draw the graph showing the way the temperature changes as stream condenses from an ice
b)calculate the amount of h2O(mass) that has been frozen

Answer 2

for a i think this is the graph,for i am not sure

Answer 3

From steam to ice the temperature drops so it will be the reverse of that graph.

Answer 4

thanks ,how about the calculation part
it seem like i only have the The latent heat of fusion
\[L_f=334J/kg\]

Answer 5

\[L_f=33.5\times 10^4\]
\[Q=mL\]

Answer 6

Are you not given anything else? What about Q?

Answer 7

does this help

Answer 8

also \[Q=mcT\]

Answer 9

Can I know what the full question is? If there are any table or diagram given?

Answer 10

ok pls give me a second

Answer 11

Sure. Do a screencap or something.

Answer 12

the information is given as follows /more detailed version

\[\large L_f=33.4\times 10^4,L_v=22.6\times 10^5\]
What mass m of water must be frozen in order to release the amount of heat that
1kg of steam releases when it condenses?

Answer 13

so this shud mean that \[Q_{ice}=Q_{steam}\]

Answer 14

Ahh that makes more sense. Ok so first find Q for 1kg of steam during condensation. Use Q=mLf. Then equate it to mLv to find m I believe.

Answer 15

this makes sense to me also ,i will post my work jus to see if it is correct

Answer 16

sorry i didnt have this information as well,my friend jus sent it now

Answer 17

It's fine. Alright. I'll make sure if I got he values right while you work it.

Answer 18

since

\[\large Q_{ice}=Q_{steam}\]

\[\large m_{ice}L_f=m_{steam}L_v\]

\[\large m_{ice}33.4\times 10^4=1*22.6\times 10^5\]

\[\large m_{ice}=6.67kg\]

Answer 19

I think that's right.