Question

The perimeter of a rectangle is 360 feet. The length is 30 feet less than three times the width of the rectangle. What are the dimensions of the rectangle.

Answer 1

x+x+30+30=360
Solve for x.

Answer 2

30ft lesst than three times the width is..
length = 3(w)-30
so the length is 3w-30, the perimeter is the sum of 2width + 2length
360=2w+2(3w-30)

Answer 3

62=360?

Answer 4

360=2w+2(3w)-2(30)
360=2w+6w-60
420=8w
witdh=420/8=52.5
length=3w-30=3(52.5)-30=127.5

Answer 5

x+x+30+30=360
2x+60=360
Subtract 60 from 360 = 300
2x=300
Divide 300 by 2.
x=150

Dimensions are 150x30

Answer 6

150/30=5

Answer 7

@calculusxy I think you're missing some information

Answer 8

@lucaz should i divide the width with 30 to get the dimension?

Answer 9

Yes I think I am. I am trying again.

Answer 10

the key is to represent the length correctly on the equation

Answer 11

I'm lost here

Answer 12

you have the width w, we don't know the value

Answer 13

we know the length is 30ft less than three times the width
this can be represented by:
length = 3(w)-30

Answer 14

yes

Answer 15

the perimeter is 2width+2length
so 360=2w+2(3w-30), find the value of w that satisfies this equation and plug it in 3(w)-30 to find the length

Answer 16

L=3w-30=3(52.5)-30=127.5

Answer 17

yes

Answer 18

ok...so how do i get the dimension from here

Answer 19

if w(the width) is 52.5 and 3w-30(the length) is 127.5
the dimensions are 52.5 by 127.5

Answer 20

52.5x127.5?

Answer 21

yes, the sides of the rectangle